If 7000 is 60% what is the original amount?

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Answer 1 · 2018-06-05T17:31:48

$11666 . ¯ 6$ $11666.bar6$

Let the original amount be x

$x \cdot 60 % = 7000$ $x * 60% = 7000$

$x \cdot 0.6 = 7000$ $x * 0.6 = 7000$

$0.6 x = 7000$ $0.6x = 7000$

$x = \frac{7000}{0.6}$ $x = 7000/0.6$

$x = 11666 . ¯ 6$ $x = 11666.bar6$

Answer 2 · 2018-06-05T17:51:13

The Original Amount is $11, 667$ $11,667$

$7000$ $7000$ is $60 %$ $60%$

Let the Orginal Amount be $x$ $x$

Therefore;

$x \times 60 % = 7000 \to from statement$ $x xx 60% = 7000 -> "from statement"$

Hence;

$60 % x = 7000$ $60%x = 7000$

Recall;

$y % = \frac{y}{100}$ $y% = y/100$

$\frac{60}{100} x = 7000$ $60/100x = 7000$

$\frac{60 x}{100} = \frac{7000}{1}$ $(60x)/100 = 7000/1$

Collecting like terms;

$60 x \times 1 = 7000 \times 100$ $60x xx 1 = 7000 xx 100$

$60 x = 700000$ $60x = 700000$

$x = \frac{700000}{60}$ $x = 700000/60$

$x \approx 11667$ $x ~~ 11667$

The Original Amount is $11, 667$ $11,667$