Solve for x? 3(2x-2)=2(x+1)

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Solve for x? 3(2x-2)=2(x+1)

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Answer 1 · 2018-06-05T18:05:57

$x = 2$ $x=2$

Explanation:

If you remember that a constant or whatever outside a parenthesis should be multiplied with each term inside the parenthesis.

Therefore,
$3 (2 x - 2) = 2 (x + 1)$ $3(2x-2)=2(x+1)$
$6 x - 6 = 2 x + 2$ $6x-6=2x+2$
Move all the unknown x-s to the left of the equal sign, and the constants to the right of the equal sign:

$6 x - 2 x = 2 + 6$ $6x-2x=2+6$
$4 x = 8$ $4x=8$
This gives $x = 2$ $x=2$

Answer 2 · 2018-06-05T18:09:10

$x = 2$ $x=2$

Explanation:

Expand the brackets:

$3 (2 x - 2)$ $3(2x-2)$ :

$3 \cdot 2 x = 6 x$ $3*2x = 6x$ and $3 \cdot - 2 = - 6$ $3*-2 = -6$

$2 (x + 1)$ $2(x+1)$ :
$2 \cdot x = 2 x$ $2*x = 2x$ and $2 \cdot 1 = 2$ $2*1 = 2$

simplify:

$6 x - 6 = 2 x + 2$ $6x-6 = 2x + 2$

bring the 2x over the equals to make it -2x which then leads to
$6 x - 2 x - 6 = 2$ $6x-2x-6=2$ $therefore$ $4x-6 = 2$
take the -6 over to make + 6 so you get:
$4x=6+2 therefore 4x=8$

divide 8 by 4 which gives 2 therefore $x = 2$

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Solve for x? 3(2x-2)=2(x+1)

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