24np/18p^2?

Question

24np/18p^2?

2 Answers

Impact of this question

1686 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-05T18:14:19

$\frac{4 n}{3 p}$ $(4n)/(3p)$

Explanation:

$= \frac{24 n p}{18 p^{2}}$ $=(24np)/(18p^2)$

$= \frac{4 n p}{3 p^{2}}$ $=(4np)/(3p^2)$

$= \frac{4 n}{3 p}$ $=(4n)/(3p)$

Answer 2 · 2018-06-05T18:18:37

$\frac{24 n p}{18 p^{2}} = \frac{4 n}{3} p)$ $(24np)/(18p^2)=(4n)/3p)$

Explanation:

I am not totally sure if I understand the expression, but it looks like n and p are two constants. If so, then we can write it as
$\frac{24 n p}{18 p^{2}}$ $(24np)/(18p^2)$
We have
$\frac{24 n p}{18 p^{2}} = \frac{(4 n) (6 p)}{(3 p) (6 p)}$ $(24np)/(18p^2)=((4n)(6p))/((3p)(6p))$
Divide numerator and denominator with $6 p$ $6p$ :
= $\frac{4 n}{3 p}$ $(4n)/(3p)$

Science

Math

Humanities

... and beyond

24np/18p^2?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question