How do you simplify $\sqrt[5]{32 x^{6}}$ $root5(32x^6)$ ?

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How do you simplify $\sqrt[5]{32 x^{6}}$ $root5(32x^6)$ ?

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Answer 1 · 2018-06-05T18:41:54

$= 2 x \sqrt[5]{x}$ $=2xroot5(x)$

Explanation:

$= \sqrt[5]{32 x^{6}}$ $=root5(32x^6)$

$= \sqrt[5]{32 x^{5} \cdot x}$ $=root5(32x^5 *x)$

$= x \sqrt[5]{32 \cdot x}$ $=xroot5(32*x)$

$= x \sqrt[5]{2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot x}$ $=xroot5(2*2*2*2*2*x)$

$= x \sqrt[5]{2^{5} \cdot x}$ $=xroot5(2^5*x)$

$= 2 x \sqrt[5]{x}$ $=2xroot5(x)$

Answer 2 · 2018-06-05T18:49:36

My thought

$\sqrt[5]{32 \cdot x^{6}} = \sqrt[5]{32} \cdot \sqrt[5]{x^{5} \cdot x} = 2 \cdot x \cdot \sqrt[5]{x}$ $root(5) (32*x^6)=root(5)32*root(5) (x^5*x)=2*x*root(5)x$

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How do you simplify $\sqrt[5]{32 x^{6}}$ $root5(32x^6)$ ?

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