Question

How to find net capacitance?

Answer 1

`4\ mu"F"`

Explanation:

The two `2\ mu"F"` capacitors are in parallel, so they can be replaced by their equivalent capacitance of `4\ mu"F"`.

This leaves us with two parallel branches, each having two `4\ mu"F"` capacitors in series.

The capacitance of each branch is `(4\ mu"F"times 4\ mu"F")/(4\ mu"F"+4\ mu"F") = 2\ mu"F"`.

So, finally we have two `2\ mu"F"` capacitors in parallel, leading to an overall equivalent capacitance of `4\ mu"F"`

Note
For two capacitors `C_1` and `C_2` in series, the equivalent capacitance is `(C_1C_2)/(C_1+C_2)`, while the equivalent of parallel capacitors is `C_1+C_2`