What is the logarithmic form of the equation $e^{5 x} = 4768$ $e^(5x) = 4768$ ?

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Answer 1 · 2018-06-06T08:30:31

Take $ln$ $ln$ in both sides

${ln e}^{5 x} = ln 4768$ $lne^(5x)=ln4768$

Using log property ${log}_{b} a^{n} = n {log}_{b} a$ $log_ba^n=nlog_ba$

$5 x \cdot ln e = ln 4768$ $5x·lne=ln4768$ but $ln e = 1$ $ln e=1$ , then

$5 x = ln 4768$ $5x=ln4768$ and finally $x = \frac{ln 4768}{5}$ $x=ln4768/5$

What is the logarithmic form of the equation e5x=4768e^(5x) = 4768?