An object is thrown vertically at a height of 7 m at 1 m/s. How long will it take for the object to hit the ground?

1 Answer
Jun 6, 2018

"1.301 s"

Explanation:

Time taken to reach the same height

t_1 = "2u"/"g"

color(white)(t_1) = "2 × 1 m/s"/"9.8 m/s"^2

color(white)(t_1) = 0.2041\ "s"

Velocity when it hits the ground

"v" = sqrt("u"^2 + "2aS")

color(white)("v") = sqrt(("1 m/s")^2 + "(2 × 9.8 m/s"^2 × "7 m)")

color(white)("v") = sqrt(138.2)\ "m/s"

color(white)("v") = 11.75\ "m/s"

Further time taken to reach the ground

t_2 = "v – u"/"g"

color(white)(t_2) = "11.75 m/s – 1 m/s"/"9.8 m/s"^2

color(white)(t_2) = 1.097\ "s"

Total time taken

"T" = t_1 + t_2 = 0.2041\ "s" + 1.097\ "s" = "1.3011 s"