How do you solve #a+ 3( 4a + 8) = 128#?

2 Answers
Jim G.
Jun 6, 2018

#a=8#

Explanation:

#"distribute and simplify the left side of the equation"#

#a+12a+24=128#

#13a+24=128#

#"subtract 24 from both sides"#

#13a=128-24=104#

#"divide both sides by 13"#

#a=104/13=8#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#8+(3xx40)=8+120=128=" right side"#

#a=8" is the solution"#

Roy Ø.
Jun 6, 2018

#a=8#

Explanation:

To solve this remember that something outside a parenthesis should be multiplied with each term inside the parenthesis.

Therefore
#a+3(4a+8)=#
#a+12a+24=#
#13a+24=128#

This gives
#13a=104#

#a=104/13=8#

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