How do you solve $(7 x - 2) - (3 x + 8) = 4 x - 10$ $(7x - 2) - ( 3x + 8) = 4x - 10$ ?

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Answer 1 · 2018-06-07T07:00:01

Any value of $x$ $x$ will make the statement true.

$7 x - 2 - 3 x - 8 = 4 x - 10$ $7x-2-3x-8 = 4x-10$

$7 x - 3 x - 4 x = - 10 + 2 + 8$ $7x-3x-4x = -10+2+8$

$0 x = 0$ $0x=0$

Any value of $x$ $x$ will make the statement true.

How do you solve (7x−2)−(3x+8)=4x−10(7x - 2) - ( 3x + 8) = 4x - 10?