Why do you factor quadratic equations?

2 Answers
Jun 7, 2018

Because it tells you what the roots of the equation are, i.e. where #ax^2+bx+c=0#, which is often a useful thing to know.

Explanation:

Because it tells you what the roots of the equation are, i.e. where #ax^2+bx+c=0#, which is often a useful thing to know.

Think of it backwards - start by knowing that the quantity #x# is zero in two places, #A# and #B#. Then two equations describing #x# are #x-A=0# and #x-B=0#. Multiply them together:
#(x-A)(x-B)=0#
This is a factored quadratic equation.

Multiply out to get the unfactored equation:
#x^2-(A+B)x+AB=0#

So when you are presented with a quadratic equation, you know that the coefficient of the #x# term is the negative of the sum of the two roots and the constant coefficient is the product of them. This knowledge is usually a help in seeing if you can easily factor a quadratic. For example:
#x^2-11x+30=0#
Now we want two numbers that add to +11 and multiply to 30; the answers are 5 and 6, we see after trying a few, so it factors as #(x-5)(x-6)=0#.

Jun 7, 2018

By factorising first and then applying the multiplication property of zero, we can solve a quadratic equation.

Explanation:

One of the properties of #0# is that :

"Anything multiplied by #0# is equal to #0#"

So, if we have an equation where:

#a xx b xx cxx d xx e =0#,

then because of the multiplication property of #0#, we will know that at least one of the factors being multiplied must be equal to #0#.

Since we can't know which one is the #0#, we consider each in turn being #0#.

#:. a =0" or " b=0" or " c=0" "or" " d=0" "o r" " e=0#

However, this is only true for FACTORS.

So to apply this concept in solving a quadratic (or cubic, quartic, etc) equation, start by factorising to find the factors.

Then let each factor be equal to #0# and solve to find the possible values of the variable.

#x^2+5x=6" "larr# of no help in this form:

#x^2+5x-6=0" "larr# make it equal to #0#

#(x+6)(x-1)=0" "larr# two factors multiply to give #0#

Let each be equal to #0#

If #x+6=0" "rarr x =-6#

If #x-1=0" "rarr x =1#

By factorising first and then applying the multiplication property of zero, we can solve the quadratic equation.