How many grams of water would require 2,153 joules of heat to raise its temperature from 44 °C to 81 °C? The specific heat of water is 4.184 J/g °C.

1 Answer
Junaid Mirza
Jun 7, 2018

"13.9 g"13.9 g

Explanation:

Use this equation

"Q = mSΔT"Q = mSΔT

Where

  • "Q ="Q = Heat added/released
  • "m ="m = Mass of sample
  • "S ="S = Specific heat of sample
  • "ΔT ="ΔT = Change in Temperature

"m" = "Q"/"SΔT"m=QSΔT

color(white)("m") = "2153 J"/"4.184 J/g°C × (81 – 44)°C"m=2153 J4.184 J/g°C × (81 – 44)°C

color(white)("m") = 13.9\ "g"

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