How do you put this quadratic equation into standard form? $20+12n=-n^2$

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Answer 1 · 2018-06-07T14:13:17

$n^2 + 12n +20 = 0$

$20 + 12n = -n^2$

Recall;

$an^2 + bn + c = 0 -> "Standard Form"$

$20 + 12n = -n^2$

Adding $n^2$ to both sides;

$20 + 12n + n^2 = -n^2 + n^2$

$20 + 12n + n^2 = 0$

Rearranging the equation;

$n^2 + 12n +20 = 0 -> "Standard Form"$

How do you put this quadratic equation into standard form? 20+12n=-n^220+12n=-n^2