What is the limit of x to infinity of x^2-3/e^x?
1 Answer
Jun 8, 2018
Explanation:
We want to evaluate the limit
#L=lim_(x->oo)(x^2-3)/e^x#
Which is an indeterminate form
So we can apply L'Hôpital's rule
#color(blue)(lim_(x->c)f(x)/g(x)=lim_(x->c)(f'(x))/(g'(x))#
Thus
#L=lim_(x->oo)(2x)/e^x#
An indeterminate form
#L=lim_(x->oo)(2)/e^x=0#