How do you simplify $8 x^{2} - 8 - [3 (x^{2} - 1) + 7]$ $8x^2-8- [3(x^2-1) +7]$ ?

Question

2342 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-08T18:34:01

5 $x^{2}$ $x^2$ -12

We will start by expanding the inner brackets.

8 $x^{2}$ $x^2$ -8-[3( $x^{2}$ $x^2$ -1)+7]

So it becomes this by multiplying 3 with $x^{2}$ $x^2$ and $- 1$ $-1$

8 $x^{2}$ $x^2$ -8-[3 $x^{2}$ $x^2$ -3+7]

Then we further simplify the insides of the brackets so it becomes,

8 $x^{2}$ $x^2$ -8-[3 $x^{2}$ $x^2$ +4]

Then we multiply $- 1$ $-1$ with the insides of the bracket, so we get:

8 $x^{2}$ $x^2$ -8-3 $x^{2}$ $x^2$ -4

Then we bring and simplify like terms together:

8 $x^{2}$ $x^2$ -3 $x^{2}$ $x^2$ -8-4

This becomes:

5 $x^{2}$ $x^2$ -12

How do you simplify 8x2−8−[3(x2−1)+7]8x^2-8- [3(x^2-1) +7]?