Question

How do you solve the system of equations `3x + 2y = 2` and `x = 2y - 10`?

Answer 1

Via Substitution

Explanation:

Input `2y-10` into the first equation wherever you see `x`

So, `3(2y-10)+2y=2`

Now you can solve for `y` the same way you would solve for `x` in this equation. (Isolate the variable and simplify until you get `y=c` where `c` is a constant [number])

then, once you've solved for `y` replace `y` with your number `c` into either equation, but solve for `x` this time.

If `y=c=-4` for example, I would solve for `x` like this

`x=2(-4)-10`
`x=-8-10`
`x=-18`
Then, I'd answer the system of equations with
`y=-4` and `x=-18`