How do you solve $\frac{x + 8}{x (x - 8)} > 0$ $(x+8)/(x(x-8)) > 0$ ?

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Answer 1 · 2018-06-09T00:55:54

$x > - 8$ $x > -8$

$\frac{x + 8}{x (x - 8)} > 0$ $(x + 8)/(x(x - 8)) > 0$

$\frac{x + 8}{x (x - 8)} > \frac{0}{1}$ $(x + 8)/(x(x - 8)) > 0/1$

Cross multiplying;

$x + 8 \times 1 > 0 [x (x - 8)]$ $x + 8 xx 1 > 0 [x(x - 8)]$

$x + 8 > 0$ $x + 8 > 0$

$x > - 8$ $x > -8$

How do you solve x+8x(x−8)>0(x+8)/(x(x-8)) > 0?