How do you simpilfy $\frac{- 5 a^{4}}{- 2 a^{3} b^{4}}$ $\frac { - 5a ^ { 4} } { - 2a ^ { 3} b ^ { 4} }$ ?

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Answer 1 · 2018-06-09T01:00:09

$\frac{5 a}{2 b^{4}}$ $(5a)/(2b^4)$

$\frac{- 5 a^{4}}{- 2 a^{3} b^{4}}$ $(-5a^4)/(-2a^3b^4)$

Note: $\frac{x^{a}}{x^{b}} = x^{a - b}$ $x^a/x^b = x^(a - b)$

$\frac{- 5 a^{4 - 3}}{- 2 b^{4}}$ $(-5a^(4 - 3))/(-2b^4)$

$\frac{- 5 a^{1}}{- 2 b^{4}}$ $(-5a^1)/(-2b^4)$

$\frac{- 5 a}{- 2 b^{4}}$ $(-5a)/(-2b^4)$

$\frac{5 a}{2 b^{4}}$ $(5a)/(2b^4)$

How do you simpilfy −5a4−2a3b4\frac { - 5a ^ { 4} } { - 2a ^ { 3} b ^ { 4} }?