How do you solve this system of equations: $y + 3 = x and 3 x + 4 y = 16$ $y+ 3= x and 3x + 4y = 16$ ?

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How do you solve this system of equations: $y + 3 = x and 3 x + 4 y = 16$ $y+ 3= x and 3x + 4y = 16$ ?

2 Answers

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Answer 1 · 2018-06-09T05:39:30

$x = 4, y = 1$ $x=4,y=1$

Explanation:

Writing $y + 3$ $y+3$ for $x$ $x$ in the second equation

$3 (y + 3) + 4 y = 16$ $3(y+3)+4y=16$
expanding
$3 y + 9 + 4 y = 16$ $3y+9+4y=16$
so $7 y = 7$ $7y=7$
$y = 1$ $y=1$

so
$x = 4$ $x=4$

Answer 2 · 2018-08-09T23:22:07

$y = 1$ $y=1$
$x = 4$ $x=4$

Explanation:

The easiest way here is by substitution. We know what $x$ $x$ is, because of the first equation so simply take what $x$ $x$ is and substitute it for $x$ $x$ in the second equation like so:

$3 (y + 3) + 4 y = 16$ $3(y+3) +4y = 16$

Distribute the 3

$3 y + 9 + 4 y = 16$ $3y + 9 +4y = 16$

Combine like terms

$7 y + 9 = 16$ $7y+ 9= 16$

solve for $y$ $y$ by subtracting 9 from both sides then dividing both sides by 7:

$y = 1$ $y=1$

plug 1 in for $y$ $y$ into either of your original equations and solve for $x$ $x$

$x = 4$ $x=4$

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How do you solve this system of equations: $y + 3 = x and 3 x + 4 y = 16$ $y+ 3= x and 3x + 4y = 16$ ?

2 Answers

Explanation:

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve this system of equations: y+ 3= x and 3x + 4y = 16y+3=xand3x+4y=16y+ 3= x and 3x + 4y = 16?

2 Answers

Explanation:

Explanation:

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Impact of this question

How do you solve this system of equations: $y + 3 = x and 3 x + 4 y = 16$ $y+ 3= x and 3x + 4y = 16$ ?