Question

A 70 kg person climbs up 2 meters in 2.8 seconds. How much energy did they gain? How much power did they use?

Answer 1

1372 J ; 490 W

Explanation:

potential energy
`E= m xx g xx h = 70 kg xx 9,8 m/s^2 xx 2 m= 1372 J`
Power is the work done (= the energy gained) in an unit of time
`P= E/t= (1372J)/ (2.8 s)= 490 W`