A .6 kg brick is dropped from a height of 8 m. It hits the ground and comes to rest. What is the magnitude of the impulse exerted by the ground on the brick?

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Answer 1 · 2018-06-09T14:04:52

$7.5 kg m/s$ $"7.5 kg m/s"$

Velocity when it hits the ground is

$v = \sqrt{2gH}$ $"v" = sqrt("2gH")$

$v = \sqrt{2 \times {9.8 m/s}^{2} \times 8 m}$ $color(white)("v") = sqrt(2 × "9.8 m/s"^2 × "8 m")$

$color(white)("v") = 12.5\ "m/s"$

Magnitude of Impulse exrted by ground on brick is

$"I = |m(v – u)"|$

$color(white)("I") = |0.6\ "kg" × "(0 m/s – 12.5 m/s)"|$

$color(white)("I") = 7.5\ "kg m/s"$