Can any anyone explain how #x^2+4x+2# become #(x-sqrt2+2)(x+sqrt2+2)# #x^2+4x+2=(x-sqrt2+2)(x+sqrt2+2)# helppppp??
3 Answers
We know that if
In order to factorize a degree two polynomial, we can use the quadratic formula suposing that
But
To check the solution we can multiply both factors and the result must be the initial polynomial
Hope this helps
Explanation:
#"given "x=a" is a root of a polynomial then"#
#(x-a)" is a factor of the polynomial"#
#"find the roots using the "color(blue)"quadratic formula"#
#"with "a=1,b=4" and "c=2#
#x=(-4+-sqrt(16-8))/2=-2+-sqrt2#
#"thus factors are"#
#(x-(-2-sqrt2))" and "(x-(-2+sqrt2))#
#(x+sqrt2+2)" and "(x-sqrt2+2)#
#rArrx^2+4x+2=(x+sqrt2+2)(x-sqrt2+2)#
Kindly refer to Explanation.
Explanation:
Completing the square of the quadr. poly.