How do you graph #y= (cosx)/x#?
1 Answer
Jun 10, 2018
there's no direct approach (as far as I know)
Explanation:
we have
plot
now plot
graph{1/x [-10, 10, -5, 5]}
notice
and resultant function is an odd function
graph{(cosx)/x [-12.66, 12.65, -6.33, 6.33]}
similarly
graph{sinx/x [-12.66, 12.65, -6.33, 6.33]}
it looks different because sinx and 1/x are both odd(graph is symmetrical) because resultant function becomes even