What are the asymptotes of #(x^2 - x + 2)/ (3x - 3)#?

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Answer 1 · 2018-06-10T21:41:42

There is one asymptote at #x=1#

Factor:

#(x^2 - x + 2)/ (3x - 3)#

#(x^2 - x + 2)/(3(x-1))#

Since no factors cancel there are no removable discontinuities (holes).

To solve the asymptotes set the denominator to 0 and solve:

#3(x-1)=0#

#x=1#

graph{(x^2 - x + 2)/ (3x - 3) [-10, 10, -5, 5]}