How do you solve $\sqrt{x + 3} = 5$ $sqrt(x+3)=5$ ?

1 Answer

Jun 11, 2018

$x = 22$ $x=22$

Explanation:

Given -

$\sqrt{x + 3} = 5$ $sqrt(x+3)=5$

${(\sqrt{x + 3})}^{2} = 5^{2}$ $(sqrt(x+3))^2=5^2$

$x + 3 = 25$ $x+3=25$

$x = 25 - 3 = 22$ $x=25-3=22$

$x = 22$ $x=22$

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How do you solve $\sqrt{x + 3} = 5$ $sqrt(x+3)=5$ ?

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