How do you multiply #(3n-2)(2n+5)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer St.Roller Jun 11, 2018 #6n^2+11n-10# Explanation: As per the question, we have #(3n-2)(2n+5)# #=(3nxx2n)+(3nxx5)+(-2xx2n)+(-2xx5)# #=6n^2+15n+(-4n)+(-10)# #=6n^2+15n-4n-10# #=6n^2+11n-10# Hence, the answer. Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1461 views around the world You can reuse this answer Creative Commons License