Differentiate the following function $\sqrt{{sec x}^{3}}$ $sqrt{secx^3$ ?

Question

Differentiate the following function $\sqrt{{sec x}^{3}}$ $sqrt{secx^3$ ?

I took the derivatives and got $\frac{1}{2} {({sec x}^{3})}^{- \frac{1}{2}} \cdot {sec x}^{3} \cdot {tan x}^{3} \cdot 3 x^{2}$ $1/2(secx^3)^(-1/2)secx^3tanx^3*3x^2$

but I'm not sure how to simplify this to find the answer

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Answer 1 · 2018-06-11T11:24:12

$\frac{3}{2} \cdot \sqrt{sec (x^{3})} \cdot x^{2} \cdot tan (x^{3})$ $3/2*sqrt(sec(x^3))*x^2*tan(x^3)$

Explanation:

it is
$\frac{1}{2} \cdot {(sec (x^{3}))}^{- \frac{1}{2}} \cdot 3 x^{2} \cdot sec (x^{3}) \cdot tan (x^{3})$ $1/2*(sec(x^3))^(-1/2)*3x^2*sec(x^3)*tan(x^3)$
which simplifies to

$\frac{3}{2} \cdot \sqrt{sec (x^{3})} \cdot x^{2} \cdot tan (x^{3})$ $3/2*sqrt(sec(x^3))*x^2*tan(x^3)$

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Differentiate the following function $\sqrt{{sec x}^{3}}$ $sqrt{secx^3$ ?

I took the derivatives and got $\frac{1}{2} {({sec x}^{3})}^{- \frac{1}{2}} \cdot {sec x}^{3} \cdot {tan x}^{3} \cdot 3 x^{2}$ $1/2(secx^3)^(-1/2)secx^3tanx^3*3x^2$

but I'm not sure how to simplify this to find the answer

1 Answer

Explanation:

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Differentiate the following function √secx3sqrt{secx^3 ?

I took the derivatives and got 12(secx3)−12⋅secx3⋅tanx3⋅3x21/2(secx^3)^(-1/2)*secx^3*tanx^3*3x^2 but I'm not sure how to simplify this to find the answer

1 Answer

Explanation:

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Impact of this question

Differentiate the following function $\sqrt{{sec x}^{3}}$ $sqrt{secx^3$ ?

I took the derivatives and got $\frac{1}{2} {({sec x}^{3})}^{- \frac{1}{2}} \cdot {sec x}^{3} \cdot {tan x}^{3} \cdot 3 x^{2}$ $1/2(secx^3)^(-1/2)secx^3tanx^3*3x^2$

but I'm not sure how to simplify this to find the answer