A corner store sells two kinds of baked goods: cakes and pies. A cake costs $14 and a pie costs $8. In one day, the store sold 12 baked goods for a total of $144. How many cakes did they sell?

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Answer 1 · 2018-06-11T11:22:39

$8$ $8$ number of cakes were sold.

Out of $12$ $12$ baked goods sold , let the number of cakes sold

be $x$ $x$ in number and pies sold were $12 - x$ $12-x$ in number.

Total sell was $$ 144$ $$144$ , $1$ $1$ cake costs $$ 14$ $$14$ and $1$ $1$ pie costs

$$8 :. 14*x + (12-x)*8=144 or 14 x -8 x =144-96$ or

$6 x= 48 :. x = 8$

Therefore, $8$ cakes were sold [Ans]

Answer 2 · 2018-06-11T11:44:51

$8$ cakes were sold

You can use two variables.

Let the number of cakes be $x$ and the number of pies be $y$

If $12$ baked goods were sold:

$x+y= 12" "rarr color(blue)(x = (12-y))$

Using the price of each we can write the equation:

$14color(blue)(x)+8y= 144$

$14(color(blue)(12-y)) +8y= 144$

$168 -14y +8y=144$

$168-144 = 6y$

$24 =6y$

$4=y$

$4$ pies were sold and $8$ cakes were sold.

Check: $8xx14 +4xx8 = 112+32=144$