Question

How do you find the x and y intercepts for `2x - 2y + 5 = 0`?

Answer 1

Intercepts such that: `(-\frac{5}{2},0)` and `(0,\frac{5}{2})`

Explanation:

The y intercept will occur when `x=0`, therefore by subbing in `x=0`, we isolate y, to form the equation:

`-2y+5=0` which we solve to find `y=\frac{5}{2}`

The x intercept occurs when `y=0` therefore do the same procedure to get:

`2x+5=0` which we solve to find `x=-\frac{5}{2}`

Answer 2

`"x-intercept "=-5/2,"y-intercept "=5/2`

Explanation:

`"to find the intercepts, that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArr-2y=-5rArry=5/2larrcolor(red)"y-intercept"`

`y=0rArr2x=-5rArrx=-5/2larrcolor(red)"x-intercept"`