How do you solve x=8-2y and x=-3y+12?
2 Answers
First solve for
Explanation:
We're very lucky for this problem, as both expressions leave
Now, we can ignore
Since
Finally, we can solve for
Explanation:
#x=8-2yto(1)#
#x=-3y+12to(2)#
#"since both equations express x in terms of y , equate"#
#"the right sides"#
#8-2y=-3y+12#
#"add "3y" to both sides"#
#8-2y+3y=12#
#"subtract 8 from both sides"#
#y=12-8=4#
#"substitute "y=4" into either of the 2 equations"#
#(1)tox=8-8=0#
#"the point of intersection "=(0,4)#
graph{(y+1/2x-4)(y+1/3x-4)=0 [-10, 10, -5, 5]}