How do you graph $f (x) = {x + 4, - 2}$ $f(x) = {x+4, -2}$ if $x > 0$ $x>0$ and if $x \leq 0$ $x<=0$ , respectively?

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Answer 1 · 2018-06-12T22:22:42

Open circle on the upper function and closed circle on the lower function.
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on the left side of the y-axis you have y=2 and on the right side of the y-axis you will have y=x+4 because of the domain restrictions.

How do you graph f(x)={x+4,−2}f(x) = {x+4, -2} if x>0x>0 and if x≤0x<=0, respectively?