What is the volume of 0.900 moles of an ideal gas at 298 K and a pressure of 1.25 atm?

1 Answer
Junaid Mirza
Jun 12, 2018

"17.6 L"17.6 L

Explanation:

Use ideal gas equation

"PV = nRT"PV = nRT

"V" = "nRT"/"P"V=nRTP

color(white)("V") = "0.900 mol × 0.0821 L atm / (mol K) × 298 K"/"1.25 atm"V=0.900 mol × 0.0821 L atm / (mol K) × 298 K1.25 atm

color(white)("V") = 17.6\ "L"

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