If $f (x) = 2 x^{2} + 1$ $f(x) = 2x^2+1$ and $g (x) = 3 x - 2$ $g(x) = 3x-2$ , what is the value of $f (g (- 2))$ $f(g(-2))$ ?

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Answer 1 · 2018-06-13T12:59:54

$f (g (- 2)) = 129$ $f(g(-2))=129$

First we need $g (- 2)$ $g(-2)$ :
$g (- 2) = 3 (- 2) - 2 = - 6 - 2 = - 8$ $g(-2)=3(-2)-2=-6-2=-8$

Now we put that value into $f (x)$ $f(x)$ :
$f (g (- 2)) = f (- 8) = 2 {(- 8)}^{2} + 1 = 2 (64) + 1 = 129$ $f(g(-2))=f(-8)=2(-8)^2+1=2(64)+1=129$

If f(x) = 2x^2+1f(x)=2x2+1f(x) = 2x^2+1 and g(x) = 3x-2g(x)=3x−2g(x) = 3x-2, what is the value of f(g(-2))f(g(−2))f(g(-2))?