How do you factor completely #3xy-4x+6y-8#?

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Answer 1 · 2018-06-13T15:15:35

#(x+2)(3y-4)#

#3xy-4x+6y-8#

rearrange:

#3xy+6y-4x-8#

factor by grouping:

#3y(x+2)-4(x+2)#

factor out #(x+2)#

#(x+2)(3y-4)#