How do you solve #t-(-1)=45#?

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Answer 1 · 2018-06-14T16:27:16

See a solution process below:

First, remember, minus a minus is a plus to rewrite the left side of the equation:

#t color(red)(-) (color(red)(-)1) = 45#

#t + 1 = 45#

Now, subtract #color(red)(1)# from each side of the equation to solve for #t# while keeping the equation balanced:

#t + 1 - color(red)(1) = 45 - color(red)(1)#

#t + 0 = 44#

#t = 44#

Answer 2 · 2018-06-14T16:27:45

#t=44#

When subtracting a negative number, the number turns positive:

#t-(-1)=45#

#t+1=45#

Now we have to variable #t# alone. To do this, subtract #1# from both sides

#t=44#

Hope this helps!