What are the quantum numbers for 5th and 6th and 7th electrons of potassium?

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What are the quantum numbers for 5th and 6th and 7th electrons of potassium?

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Answer 1 · 2018-06-14T18:39:19

Electronic configuration of potassium ( $_{19} K)$ $""_19"K")$ is

$"1s"^2\ "2s"^2\ color(red)("2p"^6)\ "3s"^2\ "3p"^6\ "4s"^1$

$5^"th", 6^"th"\ &\ 7^"th"$ electrons are in $"2p"$ subshell. Therefore their principal quantum number ( $"n"$ ) and angular momentum quantum number ( $ℓ$ ) will be $2$ and $1$ respectively.

Possible magnetic quantum numbers ( $"m"_l$ ) of $"p"$ -subshell are $-1, 0, +1$ , where $0$ is assigned to the $z$ .

Spin quantum number ( $"m"_s$ ) of first electron entering in an orbital is $pm1/2$ , since they are indistinguishable from the other one in the same orbital.

$underline(bb("Electron" color(white)(...) Orbital color(white)(no..) n color(white)(......) ℓ color(white)(.........) m_l color(white)(..../...) m_s color(white)(...)))$
$color(white)(......)5^"th" color(white)(.............) "2p"_"x" color(white)(............) 2 color(white)(.......) 1 color(white)(.....) -1 color(white)(?.) pm1/2$

$color(white)(......) 6^"th" color(white)(.............) "2p"_"z" color(white)(............) 2 color(white)(.......) 1 color(white)(..........) 0 color(white)(?.) pm1/2$

$color(white)(......) 7^"th" color(white)(.............) "2p"_"y" color(white)(............) 2 color(white)(.......) 1 color(white)(......) +1 color(white)(?.) pm1/2$

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What are the quantum numbers for 5th and 6th and 7th electrons of potassium?

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