How do you solve #2e^(12x) = 18#?

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Answer 1 · 2018-06-15T08:26:07

#x=1/color(red)(6)*ln(3)#

Simplifying we get
#e^(12x)=3^2#
taking the logarithm on both sides
#12=2ln(3)#
so
#x=1/6ln(3)#

Answer 2 · 2018-06-15T08:31:47

#color(indigo)(x = 0.1831#

#2e^(12x) = 18#

#e^(12x) = 18 / 2 = 9#

#12x log e = log 3^2, "taking log on both sides"#

#cancel(12)^color(red)(6)x log e = cancel2 log 3#

#x = (1/6) * log (3 ) / log (e) = 1.0986/6 = 0.1831#