How do you solve $2 e^{12 x} = 18$ $2e^(12x) = 18$ ?

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How do you solve $2 e^{12 x} = 18$ $2e^(12x) = 18$ ?

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Answer 1 · 2018-06-15T08:26:07

$x = \frac{1}{6} \cdot ln (3)$ $x=1/color(red)(6)*ln(3)$

Explanation:

Simplifying we get
$e^{12 x} = 3^{2}$ $e^(12x)=3^2$
taking the logarithm on both sides
$12 = 2 ln (3)$ $12=2ln(3)$
so
$x = \frac{1}{6} ln (3)$ $x=1/6ln(3)$

Answer 2 · 2018-06-15T08:31:47

$x = 0.1831$ $color(indigo)(x = 0.1831$

Explanation:

$2 e^{12 x} = 18$ $2e^(12x) = 18$

$e^{12 x} = \frac{18}{2} = 9$ $e^(12x) = 18 / 2 = 9$

$12 x log e = {log 3}^{2}, taking log on both sides$ $12x log e = log 3^2, "taking log on both sides"$

$cancel(12)^color(red)(6)x log e = cancel2 log 3$

$x = (1/6) * log (3 ) / log (e) = 1.0986/6 = 0.1831$

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How do you solve $2 e^{12 x} = 18$ $2e^(12x) = 18$ ?

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How do you solve $2 e^{12 x} = 18$ $2e^(12x) = 18$ ?