How do you divide $(26 u^{7} z^{7} - 15 u^{2} z^{7}) \div (- 3 u^{3} z^{4}$ $(26u ^ { 7} z ^ { 7} - 15u ^ { 2} z ^ { 7} ) \div ( - 3u ^ { 3} z ^ { 4}$ )?

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Answer 1 · 2018-06-15T08:38:32

$\frac{z^{3} (15 - 26 u^{5})}{3 u}$ $(z^3(15-26u^5))/(3u)$

Writing your term in the form
$- \frac{u^{2} z^{7} (26 u^{5} - 15)}{3 z^{4} u^{3}}$ $-(u^2z^7(26u^5-15))/(3z^4u^3)$
and this is

$\frac{(15 - 26 u^{5}) z^{3}}{3 \cdot u}$ $((15-26u^5)z^3)/(3*u)$

Answer 2 · 2018-06-15T08:40:30

$= \frac{- 26 u^{4} z^{3}}{3} + \frac{5 z^{3}}{u}$ $=(-26u^4z^3)/3 +(5z^3)/u$

Divide each of the terms in the first bracket by $- 3 u^{3} z^{4}$ $-3u^3z^4$

$\frac{26 u^{7} z^{7} - 15 u^{2} z^{7}}{- 3 u^{3} z^{4}}$ $(26u^7z^7-15u^2z^7)/(-3u^3z^4)$

$= \frac{27 u^{7} z^{7}}{- 3 u^{3} z^{4}} - \frac{15 u^{2} z^{7}}{- 3 u^{3} z^{4}}$ $= (27u^7z^7)/(-3u^3z^4) -(15u^2z^7)/(-3u^3z^4)$

$= \frac{- 26 u^{4} z^{3}}{3} + \frac{5 z^{3}}{u}$ $=(-26u^4z^3)/3 +(5z^3)/u$

(divide the numbers and subtract the indices)

How do you divide (26u7z7−15u2z7)÷(−3u3z4(26u ^ { 7} z ^ { 7} - 15u ^ { 2} z ^ { 7} ) \div ( - 3u ^ { 3} z ^ { 4} )?