Find a general form equation for the line through the pair of points?

(-7,-2)(7,2) and (1,6)(1,6)

1 Answer
Jun 15, 2018

y=x+5y=x+5

Explanation:

The general form of a line is y=kx+my=kx+m where k,mk,m are real numbers.

To find kk which is how steep the line is. We'll use the formula k={y_2-y_1}/{x_2-x_1}k=y2y1x2x1.

(-7, -2), (1,6)(7,2),(1,6)

Plug these values into the formula. Note how the first number in the parentheses represents the xx value and the second yy.

k={6-(-2)}/{1-(-7)}={6+2}/{1+7}=8/8=1k=6(2)1(7)=6+21+7=88=1

Insert kk into yy

y=1*x+my=1x+m

Finally, use one of the points to find mm, by inserting the (x,y)(x,y) pair into yy. I'll use the second as i think its eaiser.

6=1*(1)+m=>m=56=1(1)+mm=5

Therefore, y=x+5y=x+5