What is the slope of a line that passes through (-2, -3) and (1, 1)?

2 Answers
Jun 16, 2018

See a solution process below:

Explanation:

The formula for find the slope of a line is:

m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))m=y2y1x2x1

Where (color(blue)(x_1), color(blue)(y_1))(x1,y1) and (color(red)(x_2), color(red)(y_2))(x2,y2) are two points on the line.

Substituting the values from the points in the problem gives:

m = (color(red)(1) - color(blue)(-3))/(color(red)(1) - color(blue)(-2)) = (color(red)(1) + color(blue)(3))/(color(red)(1) + color(blue)(2)) = 4/3m=1312=1+31+2=43

Jun 16, 2018

Slope: 4/343

Explanation:

The slope of a line between two points color(blue)(""(x_1,y_1))(x1,y1) and color(green)(""(x_2,y_2))(x2,y2)
is the difference between the yy coordinate values divided by the difference between the xx coordinate values (taken in the same order);
that is
color(white)("XXX")"slope" = (color(green)(y_2)-color(blue)(y_1))/(color(green)(x_2)-color(blue)(x_1))XXXslope=y2y1x2x1

In this case we have the points color(blue)(""(-2,-3))(2,3) and color(green)(""(1,1))(1,1) (notice that the order of listing these does not matter)
So
color(white)("XXX")"slope"=(color(green)1-color(blue)(""(-3)))/(color(green)1-color(blue)(""(-2)))=4/3XXXslope=1(3)1(2)=43