How do you write $8^(-2/3)=1/4$ in logarithmic form?

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Answer 1 · 2018-06-17T08:35:30

$log_8(1/4)=-2/3$

definition of a logarithm

$log_ab=c=>a^c=b$

we have

$8^(-2/3)=1/4$

comparing this with the definition

$a=8, b=1/4, c=-2/3$

$:. log_8(1/4)=-2/3$

How do you write 8^(-2/3)=1/48^(-2/3)=1/4 in logarithmic form?