How do you solve $2 (f - 3) + 5 = 3 (f - 1)$ $2(f-3) + 5 = 3(f-1)$ ?

Question

How do you solve $2 (f - 3) + 5 = 3 (f - 1)$ $2(f-3) + 5 = 3(f-1)$ ?

1 Answer

Impact of this question

1766 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-17T12:20:26

$f = 2$ $color(blue)(f=2)$

Explanation:

Given
$XXX 2 (f - 3) + 5 = 3 (f - 1)$ $color(white)("XXX")2(f-3)+5=3(f-1)$

Simplifying each side:
$L . S .$ $L.S.$
$XXX = 2 (f - 3) + 5$ $color(white)("XXX")=2(f-3)+5$
$XXX = 2 f - 6 + 5$ $color(white)("XXX")=2f-6+5$
$XXX = 2 f - 1$ $color(white)("XXX")=2f-1$
$R . S .$ $R.S.$
$XXX = 3 (f - 1)$ $color(white)("XXX")=3(f-1)$
$XXX = 3 f - 3$ $color(white)("XXX")=3f-3$

Since $L . S . = R . S .$ $L.S.=R.S.$
$XXX 2 f - 1 = 3 f - 3$ $color(white)("XXX")2f-1=3f-3$

Subtracting $2 f$ $2f$ from both sides
$XXX - 1 = f - 3$ $color(white)("XXX")-1=f-3$
then adding $3$ $3$ to both sides
$XXX 2 = f xxxxxxxx or, if you prefer: f = 2$ $color(white)("XXX")2=fcolor(white)("xxxxxxxx")" or, if you prefer: "f=2$

Science

Math

Humanities

... and beyond

How do you solve $2 (f - 3) + 5 = 3 (f - 1)$ $2(f-3) + 5 = 3(f-1)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve 2(f−3)+5=3(f−1)2(f-3) + 5 = 3(f-1)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $2 (f - 3) + 5 = 3 (f - 1)$ $2(f-3) + 5 = 3(f-1)$ ?