Question

How do you graph `-2x+7y=-7` by plotting points?

Answer 1

Here is the graph with two key points indicated by small circles:
graph{(x^2+(y+1)^2-0.005)((x-(7/2))^2+y^2-0.005)(7-2x+7y)=0 [-0.376, 5.1, -1.764, 0.97]}

Explanation:

Since the given equation: `-2x+7y=-7` is linear,
we only need 2 points to establish the required line.

The simplest points to evaluate are
[1]`color(white)("XXX")`when `x=0rarr (x,y)=(0,-1)`
[2]`color(white)("XXX")`when `y=0rarr (x,y)=(7/2,0)`

If we plot these points on the Cartesian plane and draw a straight line through them we will get the required graph.