Question

What is the domain of `h(x)=sqrt(x-2)`?

Answer 1

`x in [2, infty)`

Explanation:

For radical functions, we cannot have a quantity less than `0` inside the square root.

In this case, we know that `h(2) = 0`, but if `x` is decreased any more than this, the radical will be undefined.

So we know that `x = 2` is the minimum value of the domain. As we increase `x`, we have no issues as the radical always contains a positive number. So `x -> infty`.

So the domain would be all values of `x >= 2`, or

`x in [2, infty)`