How do you write #root3(2x^2y)# as a fractional exponent? Algebra Exponents and Exponential Functions Fractional Exponents 1 Answer Jumbotron Jun 18, 2018 #(2x^2y)^(1/3)# Explanation: Recall; #sqrty = y^(1/2)# Also; #root(3)y = y^(1/3)# Therefore; #root(3)(2x^2y) = (2x^2y)^(1/3)# Answer link Related questions What are Fractional Exponents? How do you convert radical expressions to fractional exponents? How do you simplify fractional exponents? How do you evaluate fractional exponents? Why are fractional exponents roots? How do you simplify #(x^{\frac{1}{2}} y^{-\frac{2}{3}})(x^2 y^{\frac{1}{3}})#? How do you simplify #((3x)/(y^(1/3)))^3# without any fractions in the answer? How do you simplify #\frac{a^{-2}b^{-3}}{c^{-1}}# without any negative or fractional exponents... How do you evaluate #(16^{\frac{1}{2}})^3#? What is #5^0#? See all questions in Fractional Exponents Impact of this question 1558 views around the world You can reuse this answer Creative Commons License