How do you write $\sqrt[3]{2 x^{2} y}$ $root3(2x^2y)$ as a fractional exponent?

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Answer 1 · 2018-06-18T01:51:03

${(2 x^{2} y)}^{\frac{1}{3}}$ $(2x^2y)^(1/3)$

Recall;

$\sqrt{y} = y^{\frac{1}{2}}$ $sqrty = y^(1/2)$

Also;

$\sqrt[3]{y} = y^{\frac{1}{3}}$ $root(3)y = y^(1/3)$

Therefore;

$\sqrt[3]{2 x^{2} y} = {(2 x^{2} y)}^{\frac{1}{3}}$ $root(3)(2x^2y) = (2x^2y)^(1/3)$

How do you write 3√2x2yroot3(2x^2y) as a fractional exponent?