What is the domain of $y = \sqrt{x + 16}$ $y=sqrt(x+16)$ ?

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Answer 1 · 2018-06-18T02:14:46

$x \in [- 16, \infty)$ $x in [-16, infty)$

The domain is restricted by where the quantity $x + 16 \geq 0$ $x+16 >=0$

This means that $x \geq - 16$ $x >= -16$

There is no restriction on how large $x$ $x$ can be, as the quantity is always positive.

So the domain is

$x \in [- 16, \infty)$ $x in [-16, infty)$

What is the domain of y=√x+16y=sqrt(x+16)?