Question

How do you solve `2( c - 4) + 8= \frac { 1} { 2} ( 6c + 20)`?

Answer 1

`c=-10`

Explanation:

`"distribute brackets on both sides"`

`2c cancel(-8)cancel(+8)=3c+10`

`2c=3c+10`

`"subtract "2c" from both sides"`

`0=c+10`

`"subtract 10 from both sides"`

`-10=crArrc=-10`

Answer 2

`c=-10`

Explanation:

If `2(c-4)+8=1/2(6c+20)`
we have
`4(c-4)+16=6c+20`
`4c-16+16=6c+20`
`4c=16c+20`
Move all the c terms to the left and the constants to the right of the equality sign:
`4c-6c=20`
`-2c=20`
`c=-10`