How do you evaluate #int [x / sqrt (2x-1)]dx# for [1, 5]?
3 Answers
Explanation:
Let,
Now, recall that,
Explanation:
Let
Indefinite
Apply linearity
Apply power rule
Undo substitution
Explanation:
Let
Then,
Using this, we can say that:
The reason why we did all this calculation is so that we can turn
into a simpler integral of:
Notice that the ranges have changed. This is because the variable have changed to
Assuming that you know how to do basic integrals, I will skip the steps to solve the above expression.
After solving the above:
Hope that makes sense! If it doesn't make sense, feel free to comment any questions.