How do you solve #(x-1)/(x+1)= (-3x)/(2x+2) + x/(6x+6)#?

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Answer 1 · 2018-06-18T07:45:15

#x=6/14 or x=-1#

Need to get denominator same for the two additions

#(-3x(6x+6)+x(2x+2))/((2x+2)(6x+6))#

#(-18x^2-16x)/((2x+2)(6x+6))#

#(-8x(2x+2))/((2x+2)(6x+6))#

#(-8x)/(6x+6)=(x-1)/(x+1)#

#-8x(x+1)=(6x+6)(x-1)#

#-8x^2-8x=6x^2-6#

#0=14x^2+8x-6#

#0=(14x-6)(x+1)#