How do you solve # 8x-1=63#?
3 Answers
Explanation:
#"isolate "8x" by adding 1 to both sides of the equation"#
#8x=63+1=64#
#"divide both sides by 8"#
#(cancel(8) x)/cancel(8)=64/8rArrx=8#
#color(blue)"As a check"#
#(8xx8)-1=64-1=63larr"correct"#
x = 8
Explanation:
Using Addition/Subtraction, 'move' all the constants to one side of the equation, and then divide through by
Explanation:
Our goal is to get
The first step is to get all constants to the opposite side of the equation as
Next, we need to eliminate