How do you solve $\frac{49}{15 x} = \frac{11}{3 x} - \frac{2}{15}$ $\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}$ ?

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Answer 1 · 2018-06-20T14:58:39

$x = 3$ $x=3$

Multiply the entire equation by the common denominator $15 x$ $15x$

$\frac{49}{15 x} = \frac{11}{3 x} - \frac{2}{15}$ $\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}$

$15 x [\frac{49}{15 x} = \frac{11}{3 x} - \frac{2}{15}]$ $15x[\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}]$

$49 = 5 \cdot 11 - 2 \cdot x$ $49 = 5*11-2*x$

$49 = 55 - 2 x$ $49 = 55-2x$

$- 6 = - 2 x$ $-6= -2x$

$x = 3$ $x=3$

Answer 2 · 2018-06-20T15:02:00

Add $\frac{2}{15}$ $2/15$

$\frac{49}{15 x} + \frac{2}{15} = \frac{11}{3 x}$ $49/[15x]+2/15=11/[3x]$

Subtract $\frac{49}{15 x}$ $49/[15x]$

$\frac{2}{15} = \frac{11}{3 x} - \frac{49}{15 x}$ $2/15=11/[3x]-49/[15x]$

$\frac{2}{15} = \frac{55}{15 x} - \frac{49}{15 x}$ $2/15=55/[15x]-49/[15x]$

$\frac{2}{15} = \frac{6}{15 x}$ $2/15=6/[15x]$

Cross multiply

$15 x \times 2 = 16 \times 6$ $15x xx 2 = 16 xx 6$

$30 x = 96$ $30x=96$

divide by 30

$x = \frac{96}{30} = \frac{32}{10} = 3.2$ $x=96/30=32/10=3.2$

How do you solve \frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}4915x=113x−215\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}?